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It is no secret that the overwhelming number of computer users use convenient and compact laptops as such. At the same time, the touchpad never became a full-fledged, and most importantly, convenient replacement for a mouse. The most convenient option for working on a laptop is to use a wireless mouse that runs on AAA batteries.
After several cases of the mouse batteries being discharged at the most inopportune moment, when there was no outlet at hand, I came up with the idea of ​​​​creating a universal charger from improvised means that allows you to charge the batteries from a laptop.

Universal usb charger


For greater versatility, the ability to charge a phone was also added by connecting a plug in parallel to charge the phone, as a result, even while on the road, you can charge your mobile phone without any problems.



And so, to create this device, we used the back part of a broken control panel, for example from a TV. In general, the main thing is that there is a working compartment for AAA batteries, we just need to take it and saw it off for later use in the device.



Now we already have a compartment for batteries, then we take any old charger and cut off the plug on it, as a rule, there will be two wires - red (+) and black (-), the main thing is not to confuse it. It is strictly forbidden to connect the charger directly to the batteries for your own safety; the power source to the batteries will be connected through a special microcircuit, which is found in any telephone battery; it serves precisely to limit the power supply when the batteries are fully charged.



Connecting this circuit is not difficult; the advantage for the charger will be the contact soldered to the body of the battery itself, although in fact each contact is usually labeled, the main thing is not to confuse the input with the output.



The next step is to install a mini usb socket in the device, it can be taken from any broken player or phone, connecting it is very simple: the first contact is plus, the fifth is minus, it should be connected to the input above the specified microcircuit.




For indication, charger operation, convenient to use Light-emitting diode taken, for example, from a lighter with a flashlight, it must be soldered through a resistance of 150 to 500 Ohms to the outputs of the microcircuit.



Having collected all this, we get a universal charger with the ability to charge the phone and batteries, both from a laptop or computer, and from the network.


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Comments (8)
  1. Veent
    #1 Veent Guests 17 May 2013 22:49
    0
    The idea is wonderful, but I don’t fully understand why if the battery voltage is 3 V (1.5x2) And we supply 5 V. It’s just that, as far as I remember, when charging a telephone battery (3.7 V) directly (from the power supply) when 5 V is supplied, the current exceeds 2 A and usb gives only 0.5 A
  2. Ruslan
    #2 Ruslan Guests 28 May 2013 14:24
    0
    Quote: Veent
    The idea is wonderful, but I don’t fully understand why if the battery voltage is 3 V (1.5x2) And we supply 5 V. It’s just that, as far as I remember, when charging a telephone battery (3.7 V) directly (from the power supply) when 5 V is supplied, the current exceeds 2 A and usb gives only 0.5 A

    It is for the purpose of stabilizing the voltage in accordance with what the batteries need that the described microcircuit is installed; it supplies electricity based on two parameters, such as the capacity and resistance of the batteries.
  3. Eugene
    #3 Eugene Guests 16 September 2013 19:33
    0
    Quote: Ruslan
    Quote: Veent
    The idea is wonderful, but I don’t fully understand why if the battery voltage is 3 V (1.5x2) And we supply 5 V. It’s just that, as far as I remember, when charging a telephone battery (3.7 V) directly (from the power supply) when 5 V is supplied, the current exceeds 2 A and usb gives only 0.5 A

    It is for the purpose of stabilizing the voltage in accordance with what the batteries need that the described microcircuit is installed; it supplies electricity based on two parameters, such as the capacity and resistance of the batteries.

    can I have a diagram? since it’s not clear where to solder Light-emitting diode, to which pins of the microcircuits and where exactly, without a diagram it’s difficult to understand anything
  4. Andrey
    #4 Andrey Guests 22 September 2013 14:20
    0
    complete nonsense...
    An AAA or AA 1.2V battery is considered charged when it reaches 1.4V. 2 batteries connected in series should reach 2.8V respectively. But the Li-ion battery controller will turn off your AAA batteries when they reach 4.2V, which will inevitably lead to their failure due to overcharging (not on the first day, but after a week).
    But this circuit is more or less suitable for a battery made up of three identical AAA or AA batteries connected in series. The controller will turn them off just when they reach a total of 4.2V. When such a battery is discharged under load, the controller will turn it off when the voltage reaches 2.8V, which is not dangerous for Ni-MH batteries.
  5. Gleb
    #5 Gleb Guests 19 February 2014 12:57
    0
    Quote: Evgeniy
    Quote: Ruslan
    Quote: Veent
    The idea is wonderful, but I don’t fully understand why if the battery voltage is 3 V (1.5x2) And we supply 5 V. It’s just that, as far as I remember, when charging a telephone battery (3.7 V) directly (from the power supply) when 5 V is supplied, the current exceeds 2 A and usb gives only 0.5 A

    It is for the purpose of stabilizing the voltage in accordance with what the batteries need that the described microcircuit is installed; it supplies electricity based on two parameters, such as the capacity and resistance of the batteries.

    can I have a diagram? since it’s not clear where to solder Light-emitting diode, to which pins of the microcircuits and where exactly, without a diagram it’s difficult to understand anything
  6. Gleb
    #6 Gleb Guests 11 July 2014 18:13
    0
    Quote: Gleb
    Quote: Evgeniy
    Quote: Ruslan
    Quote: Veent
    The idea is wonderful, but I don’t fully understand why if the battery voltage is 3 V (1.5x2) And we supply 5 V. It’s just that, as far as I remember, when charging a telephone battery (3.7 V) directly (from the power supply) when 5 V is supplied, the current exceeds 2 A and usb gives only 0.5 A

    It is for the purpose of stabilizing the voltage in accordance with what the batteries need that the described microcircuit is installed; it supplies electricity based on two parameters, such as the capacity and resistance of the batteries.

    can I have a diagram? since it’s not clear where to solder Light-emitting diode, to which pins of the microcircuits and where exactly, without a diagram it’s difficult to understand anything

    Thanks to the author =)
  7. Vlad
    #7 Vlad Guests September 27, 2017 02:41
    0
    Quote from Andrey:
    "2 batteries connected in series should reach 2.8V respectively. But the Li-ion battery controller will turn off your AAA batteries when they reach 4.2V, which will inevitably lead to their failure due to overcharging."
    -Connect rectifier diodes (2, 3 pieces) in series with the batteries, selecting the voltage drop.
    1. Yuri Vasilievich
      #8 Yuri Vasilievich Guests August 31, 2019 00:12
      0
      Wouldn’t it be more convenient to plug it into a normal charger and not worry about the batteries lest they fail ahead of time?

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